SOLUTION: Use an Algebraic equation to determine each rectangle's dimensions.
An American football field is a rectangle with a perimeter of 1040 feet. The length is 200 feet more than the
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Question 1153483: Use an Algebraic equation to determine each rectangle's dimensions.
An American football field is a rectangle with a perimeter of 1040 feet. The length is 200 feet more than the width. Find the width and length of the rectangular field.
Thank you in advance,
SYL
Found 2 solutions by greenestamps, MathLover1:
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!
w = width; w+200 = length
perimeter = 2(length+width)
Solve using basic algebra....
Without algebra....
Imagine shortening the field by 200 feet, so that the length and width are the same. That makes the perimeter 1040-400 = 640 feet.
With length and width the same, the field is square; each side is one-quarter of the perimeter: 640/4 = 160.
So the width of the field is 160 feet.
Now add the 200 feet back on to the length to get 360 feet for the length.
ANSWER: width 160 feet; length 360 feet
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
An American football field is a with a perimeter of .
the perimeter of a is:
....if
........eq.1
if the length is than the width, we have
........eq.2
go to
........eq.1, substitute
........solve for
go to
........, substitute
answer: the width is and length of the rectangular field is
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