SOLUTION: Jack measures the angle of elevation to the top of a 250 ft high telecommunications tower to be 33 degrees and the angle of depression to the base of the tower to be 16 degrees.
a
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Question 1153327: Jack measures the angle of elevation to the top of a 250 ft high telecommunications tower to be 33 degrees and the angle of depression to the base of the tower to be 16 degrees.
a) Sketch and label a diagram of the situation.
b) How far is jack from the tower?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You can make the drawing. Triangle assigning any point names you want to. Try T, B, J for points at Top of the tower, Bottom of tower, Jack's location.
Make perpendicular segment to TB, point A so that AJ is perpendicular to TB. Segment AT is 250 feet.
Angle AJT is 33 degrees.
Angle AJB is 16 degrees.
Choose either of the right triangles you like to answer the question. The upper triangle may be easier.
385 feet to the nearest whole number
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