SOLUTION: in triangle ABC given that angle B=45 degrees, angle C=30 degrees, side a=10, find angle A and sides b and c? can anyone show me step by step instruction thanks

Question 115270: in triangle ABC given that angle B=45 degrees, angle C=30 degrees, side a=10, find angle A and sides b and c?
can anyone show me step by step instruction thanks
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
in triangle ABC given that angle B=45 degrees, angle C=30 degrees, side a=10, find angle A and sides b and c?
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angle A = 180 -(45+30) = 105
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Use Law of Sines to get:
b/sin(B) = a/sin(105)
b/sin(45) = 10/sin(105)
b = 10*sin(45)/sin(105)
b = 7.32...
------------------------
c/sin(C) = a/sin(105)
c/sin(30) = 10/sin(105)
c = 10sin(30)/sin(105
c= 5.176...
----------------
Cheers,
Stan H.

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