SOLUTION: A guy wire is anchored 12 feet from the base of a pole. The wire makes a 58 o angle with the ground. To the nearest foot how long is the wire?

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Question 1144296: A guy wire is anchored 12 feet from the base of a pole. The wire makes a 58 o angle with the ground. To the nearest foot how long is the wire?
Found 3 solutions by Theo, MathTherapy, ikleyn:
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
let the horizontal leg of the right triangle formed be equal to x.
let the vertical leg of the right triangle formed be equal to y.
the angle of 58 degrees is formed between the horizontal leg and the hypotenuse of the right triangle formed.
the tangent of this angle is equal to the side opposite the angle divided by the side side adjacent to the angle.
the side adjacent to the angle is not the hypotenuse of the triangle.
you get tan(58) = y/x.
since x = 12, you get tan(58) = y/12
multiply both sides of this equation by 12 to get 12 * tan(58) = y
solve for y to get y = 19.20401435 feet.
round to the nearest foot to get y = 19 feet.

Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

A guy wire is anchored 12 feet from the base of a pole. The wire makes a 58 o angle with the ground. To the nearest foot how long is the wire?
Correct answer: 22.64495898, which when rounded to the nearest foot, becomes:  

Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
 .


You have a right-angled triangle with the horizontal leg of 12 feet on the ground 

and the attached acute angle of 58°.


They ask you about the length of the hypotenuse "c".


Use the equation   = cos(58°)  and get  c =  =  = 22.626.


ANSWER.  Approximately  23 feet  (rounded to the nearest longer foot)





 

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