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In order for three segments of the length a, b and c form a triangle, three "triangle inequalities" must be satisfied
a + b > c,
a + c > b,
b + c > a.
In wording form, it means that the sum of any two side lengths must be greater than the length of the third side.
In our case,
19 + 10 = 29,
but inequality
19 + 10 > 29
is not held.
Therefore, the given three segments do not form a triangle.
Answered, explained and completed.
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I wrote my post because the post by @josgarithmetic does not explain the subject correctly and only can mislead a young inexperienced student.
My advise to any reader who will see my post, is to ignore writing by @josgarithmetic, since it may harm your mind.
I'd called it "one more fake solution from @josgarithmetic", but it would be too soft / (gentle) name for it . . .
"RUBBISH" is a correct name.
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It is paradoxically, but @josgarithmetic, being a totally unqualified as a tutor and producing tons and thousands
fake solutions, collects enthusiastic feedback from the visitors, much more than any other tutor in this forum.
I thought long time about it, and came to the conclusion, that it tells a lot about the visitors.