SOLUTION: In triangle ABC, AB= 7, BC= 24, and AC= 25. What is the distance from vertex B to side AC?

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Question 1131574: In triangle ABC, AB= 7, BC= 24, and AC= 25. What is the distance from vertex B to side AC?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Draw your description. Including altitude from B to AC you can call the left segment along AC as x and the right segment along AC as 25-x. Let y be the length of the altitude.


Just a start:


Solve for the value of y.

If substitute for y^2, then .... .

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Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
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The triangle is a right angled triangle with the right angle at B.


The simplest way to check it is this:

     =  = (25-24)*(25+24) = 1*49 = 49 =  = .


Let H be the distance under the question. Notice that H is nothing else as the altitude of the triangle ABC drawn from 
the right angle vertex B to the hypotenuse AC.


Then we have two expressions for the triangle area 

    Area =  = .


It gives  H = .     ANSWER

Solved.

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It is how this problem has to be solved.



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