SOLUTION: In triangle ABC, B is 15 less than two times A. If C is 3 degrees larger than B, find the three angles. a+b+c=180 b=a.a-15 c=b+3 b= (a2-15)+3 b= (

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Question 1125493: In triangle ABC, B is 15 less than two times A. If C is 3 degrees larger than B, find the three angles.
a+b+c=180
b=a.a-15
c=b+3
b= (a2-15)+3
b= (
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
In triangle , the three angles
->....eq.1
if is less than times ,we have

....eq.2

if is degrees than,we have
....eq.3

go to ....eq.1, substitute and from eq.2 and eq.3
..........solve or








then



and




check the sum:
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
In triangle ABC, B is 15 less than two times A. If C is 3 degrees larger than B, find the three angles.
a+b+c=180
b=a.a-15
c=b+3
b= (a2-15)+3
b= (
Let angle A be A

Then angle B = 2A - 15

And, angle C = 2A - 15 + 3, or 2A - 12

As the 3 angles sum to 180o, we get: A + 2A - 15 + 2A - 12 = 180

5A = 207

Solve that for A, angle A's measurement.

Subtract 15 from TWICE A to get B's measurement.

Subtract 12 from TWICE A to get C's measurement.

That's it!! It's as SIMPLE as that!! 

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