SOLUTION: What is the value of y?
Enter your answer in the box.
y =
An isosceles triangle with vertices labeled A, B, and C. Side B C is the base. Sides A B and A C are equal. S
Algebra.Com
Question 1103272: What is the value of y?
Enter your answer in the box.
y =
An isosceles triangle with vertices labeled A, B, and C. Side B C is the base. Sides A B and A C are equal. Sides A B and A C are labeled with single tick marks. Angle A is labeled as left parenthesis 4 y plus 10 right parenthesis degrees, angle B is labeled as 75 degrees, and angle C is labeled as left parenthesis 3 x right parenthesis degrees.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
If using A, B, C, as variables for the measure of the corresponding interior angles, and A is the vertex point, B and C are the base angles, triangle isosceles, then:
Angle mesures at B and C are equal (base angles of isosceles triangle).
What about A?
Both B and C each is 75 degrees.
, sum of interior angles of any triangle;
and you wer given an expression for measure of angle A.
RELATED QUESTIONS
What is the area of this triangle?
Enter your answer as a decimal in the box. Round... (answered by Fombitz,ikleyn,MathTherapy)
Parallelogram ABCD is a rectangle.
AC=2y+7
BD=3y−4
What... (answered by MathLover1)
In △ABC, DG=32 cm .
What is the length of ADŻŻŻŻŻ?
Enter... (answered by ikleyn)
ASK YOUR TEACHER
The lengths of two sides of the right triangle ABC shown in the... (answered by josgarithmetic)
Solve for y.
y =
An equilateral triangle A B C. Side B C is the base. Sides A B, B... (answered by greenestamps)
Analytic Geometry
1.a) Draw the triangle with vertices P(-2,-2), Q(2,4), and R(8,0).... (answered by Fombitz)
show that the triangle with vertices at A(-2,4) B(-5,1) and C(-6,5) is... (answered by Alan3354)
The lengths of two sides of the right triangle ABC shown in the illustration are given.... (answered by josgarithmetic)
Which is the smallest possible answer for an isosceles triangle, if one side is 18cm and (answered by solver91311)