SOLUTION: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 20 square feet, find the length of the sides of the poster

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Question 1099778: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 20 square feet, find the length of the sides of the poster and the sign
Answer by ikleyn(52905)   (Show Source): You can put this solution on YOUR website!
.
 -  = 20  ====>

 = 20  ====>

4x = 20 + 4 = 24   ====>  x = 6.


Answer.  The larger square has the side length of 6 feet.

         The smaller square has the side length of 4 feet.

         6^2 - 4^2 = 36 - 16 = 20.   ! Correct !

Solved.


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