SOLUTION: a fountain is located between two trees. each tree had a height of 60 feet. the angles of elevation from the base of the fountain to the top of each tree are 64 degrees and 48 degr

Question 1078307: a fountain is located between two trees. each tree had a height of 60 feet. the angles of elevation from the base of the fountain to the top of each tree are 64 degrees and 48 degrees as shown below. what is the horizontal distance between the two trees (rounded to the nearest foot)?
Found 2 solutions by dkppathak, josgarithmetic:
Answer by dkppathak(439) (Show Source): You can put this solution on YOUR website!
a fountain is located between two trees. each tree had a height of 60 feet. the angles of elevation from the base of the fountain to the top of each tree are 64 degrees and 48 degrees as shown below. what is the horizontal
by ht and distance
60/x=tan64 tan 64=2.0503
x=60/2.0503
x=29.26
similarly
60/y= tan 48 tan 48=1.1106
y=60/1.1106
y=54.0248
total distance between two tree is 29.26+54.0248=83.2848 m

Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
The two lengths on the ground from each tree,
and .

, to nearest foot
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