SOLUTION: In triangle ABC , m<B = 60 degree. Prove that m( AC)^2=(mAB)^2+(mBC)^2-(mAB).(mCB)

Question 1067187: In triangle ABC , m m( AC)^2=(mAB)^2+(mBC)^2-(mAB).(mCB)

Answer by ikleyn(52814) (Show Source): You can put this solution on YOUR website!
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