SOLUTION: In triangle LMN, L = 27.0 cm, m = 31.4 cm, and <N = 82�. Determine the measure of n to the nearest tenth of a centimetre.

Question 1062623: In triangle LMN, L = 27.0 cm, m = 31.4 cm, and Determine the measure of n to the nearest tenth of a centimetre.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
Points L, M, N
MN = 27.0
LN = 31.4
Find LM length.

Your composition field shows this but here, making a small change wording :
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In triangle LMN, L = 27.0 cm, m = 31.4 cm, and angle measure at N = 82�.
Determine the measure of n to the nearest tenth of a centimetre.
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That means the interior angle between segments MN and LN is 82 degrees.

The question is asking for the length of segment LM.

Use Law Of Cosines.

Answer by ikleyn(52847) (Show Source): You can put this solution on YOUR website!
.
In triangle LMN, L = 27.0 cm, m = 31.4 cm, and Determine the measure of n to the nearest tenth of a centimetre.
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The condition DOES NOT provide enough data to solve the problem.

Check your input.

Writing by "josg" doesn't make sense. Simply ignore it.

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