SOLUTION: In a right angled triangle if one of the acute angle is double the other then prove that hypotenuse is double the smallest side of the triangle.

SOLUTION: In a right angled triangle if one of the acute angle is double the other then prove that hypotenuse is double the smallest side of the triangle.

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Question 1057015: In a right angled triangle if one of the acute angle is double the other then prove that hypotenuse is double the smallest side of the triangle.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
In a right angled triangle if one of the acute angle is double the other then prove that hypotenuse is double the smallest side of the triangle.
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The angles are 30 & 60 degs.
sin(30) = a/hyp = 1/2

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