SOLUTION: Show graphically that -(a-b)=-a+b

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Question 1045300: Show graphically that -(a-b)=-a+b
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
let x = a and y = b.

your equation becomes:

-(x - y) = -x + y

simplify to get -x + y = -x + y

add x to both sides of the equation and subtract y from both sides of this equation to get:

-x + x + y - y = -x + x + y - y, which results in:

0 = 0

since all the variables disappeared from the equation and the equation is true, this means that any values of x and y will satisfy the original equation.

in other words, the equation is an identity.

for example:

let x = 15 and y = 20 (numbers off the top of my head).

-(x - y) = -x + y becomes:

-(15 - 20) = -15 + 20

simplify to get:

-15 + 20 = -15 + 20

it's plain to see that this equation is true.

if you add 15 to both sides of this equation and subtract 20 from both sides of this equation, you will get:

0 = 0

now to graphing this equation.

what i find is that it doesn't graph on a 2 dimensional plane.

it does graph on a 3 dimensional planes and the result is that z = 0.

on a 2 dimensional plane, you start out with:

-(x-y) = -x + y

to graph this, you solve for y.

start with -(x-y) = -x + y

simplify to get -x + y = -x + y

add x to both sides of this equation and subtract y from both sides of this equation to get:

0 = 0.

there's nothing to graph.

on a 3 dimensional plane, you get:

z1 = -(x - y)

z2 = -x + y

set z = z1 - z2.

this becomes z = -(x - y) - (-x + y) which becomes z = -x + y + x - y which becomes z = 0.

the 3 dimensional graph is a plane at z = 0.

this means that any value of x and y will make z = 0.

the 2 dimensional graph will show nothing.

the 3 dimensional graph will show z = 0.

here's what the 3 dimensional graph will look like.

$$$

the plane is empty which means that any value of x and y will satisfy the equation.


























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