SOLUTION: Triangle abc whose sides are ab and bc are 5m and 4m respectively and on angle b 130 degree make an angle outside the triangle. Find length of ac.

Question 1041202: Triangle abc whose sides are ab and bc are 5m and 4m respectively and on angle b 130 degree make an angle outside the triangle. Find length of ac.
Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Triangle abc whose sides are ab and bc are 5m and 4m respectively and on angle b 130 degree make an angle outside the triangle. Find length of ac.
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Sounds like the interior angle at "b" is 50 degrees
Also, side ac is opposite that 50 degree angle.
Using Law of Cosines::
ac = 4^2 + 5^2 - 2*4*5*cos(50 deg)
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ac = 28.14m
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Cheers,
Stan H.

Answer by ikleyn(52855) (Show Source): You can put this solution on YOUR website!
.
In the previous tutor solution

|AC|^2 = 4^2 + 5^2 - 2*4*5*cos(50 deg),

|AC| = m =~ 5.30 m.

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