SOLUTION: I am confused on what to draw out as triangles, since there are no pictures. Thanks in advance!
Given the triangle ADC, segment BD is a perpendicular bisector of segment AC. P
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Question 1040833: I am confused on what to draw out as triangles, since there are no pictures. Thanks in advance!
Given the triangle ADC, segment BD is a perpendicular bisector of segment AC. Point B is the median of side AC. Why would triangle ABD be similar to triangle CBD?
*SAS
*CPCTC
*SSS
*AAS
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
BD is congruent to BD by Reflexive Equality
AB is congruent to BC by definition of bisector.
Angle DBA is congruent to angle DBC by definition of perpendicular.
Triangle DBA congruent to triangle DBC by SAS
John

My calculator said it, I believe it, that settles it

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