SOLUTION: In a triangle ABC, angle A = 2 angle B. How would you prove that BC² = AC² + AB × AC?
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Question 1035292: In a triangle ABC, angle A = 2 angle B. How would you prove that BC² = AC² + AB × AC?
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Use law of sines. Here
.
Cross-multiplying, this is equivalent to
.
Applying the law of cosines, we have
This is equivalent to
.
Substituting we have
You can then solve for
. However I don't think what I got matches with the expression you provided (either I messed up my algebra or the question you typed is incorrect).
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