SOLUTION: Solve using the sine rule in Triangle ABC, DA=59degrees, DB=39degrees, and A=6.73. Find angle c, sides b and c?

Question 1025294: Solve using the sine rule in Triangle ABC, DA=59degrees, DB=39degrees, and A=6.73. Find angle c, sides b and c?
Found 2 solutions by Cromlix, Fombitz:
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Angle C = 180 - (59 + 39)
Angle C = 82 degrees.
........
a/Sin(a) = b/Sin(b)
6.73/sin(59) =b/sin (39)
b = (6.73 x sin(39))/sin(59)
b = 4.94 (2 decimal places)
........
a/Sin(a) = c/Sin(c)
6.73/sin(59) = c/sin(82)
c = (6.73 x sin(82))/sin(59)
c = 7.78 (2 decimal places)
Hope this helps :-)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

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