SOLUTION: Find the perimeter of the triangle with the vertices at (1, 2), (-6, 5), and (-6, -4).

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Question 1017292: Find the perimeter of the triangle with the vertices at
(1, 2), (-6, 5), and (-6, -4).

Found 3 solutions by NotAnotherSecret, Alan3354, MathTherapy:
Answer by NotAnotherSecret(1)   (Show Source): You can put this solution on YOUR website!
Well, First use a graph and plot the vertices. then count that blocks on the outside of the triangle. This is the perimeter. A good way to remember is peRIMeter.


Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Find the perimeter of the triangle with the vertices at
(1, 2), (-6, 5), and (-6, -4).
---------------
Use the distance formula to find the 3 side lengths.
Perimeter = the sum of the 3 lengths.
----
A(1,2), B(-6,5), and C(-6,-4)
Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

Find the perimeter of the triangle with the vertices at
(1, 2), (-6, 5), and (-6, -4). 
You need to use the distance formula to find the length of the line connecting points (1, 2) & (- 6, 5), and (1, 2) & (- 6, - 4). 



You do not need to do this for the line connecting (- 6, 5) and (- 6, - 4) since these points' x-coordinates are the same, hence a vertical line

that's parallel to the y-axis. This length is found by merely taking the absolute value of the difference between the y-coordinates.

This is: either: , or . You could also subtract the smaller value (- 4) from the larger value (5). 

Do you now see the length of this side? I sure hope so! 

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