Something is wrong. If two triangles are similar, the three angles of one are equal in measure to the corresponding three angles of the other. You have mentioned that two of the angles of ΔKSD are ∠K=16° and ∠D=34°. So that would mean that ∠S=130°, because∠K+∠D+∠S=180°. That's because all the angles of any triangle must total 180°. But you also say that ∠T=51°. But since no angle of ΔKSD can equal 51°, neither can any angle of ΔWAT equal to 51°. Therefore ∠T=51° is impossible! If you can explain the figure a little better, you may do so in the thank-you note form below. I will get back to you by email. Edwin