SOLUTION: Find two consecutive odd integers such that their product is 31 more than 2 times their sum.

Algebra.Com
Question 1014564:
Find two consecutive odd integers such that their product is
31
more than
2
times their sum.

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Let represent the smaller of the two odd integers, then must be the next consecutive odd integer.

The product of the two consecutive odd integers is

Two times the sum of the two consecutive odd integers is

So, if the product is 31 larger than twice the sum:







So if , then

7 times 9 is 63 which is 31 larger than 32 which is 2 times 16 which is 7 plus 9

But if , then

-5 times -3 is 15 which is 31 larger than -16 which is 2 times -8 which is -5 plus -3.

John

My calculator said it, I believe it, that settles it

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