SOLUTION: the vertex angle of an isosceles triangle is twice as large as one of the base angles. Find the measure of the vertex angles.

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Question 1012489: the vertex angle of an isosceles triangle is twice as large as one of the base angles. Find the measure of the vertex angles.
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52834)   (Show Source): You can put this solution on YOUR website!
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the vertex angle of an isosceles triangle is twice as large as one of the base angles. Find the measure of the vertex angles.
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Answer. 90 degrees.


Solution

Let m be the measure of the angle at the base. Then the other angle at the base has the same measure m as the triangle is isosceles.

The vertex angle is 2m according to the condition.

Since the sum of interior angles of a triangle is 189 degrees, it gives you an equation

m + m + 2m = 180,   or  4m = 180.

Hence, m =  = 45 degrees for the angle at the base.

It gives 90 degrees for the vertex angle.

The problem is solved.


Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
the vertex angle of an isosceles triangle is twice as large as one of the base angles. Find the measure of the vertex angles.
Let measure of vertex angle, be V
Then each congruent base angle = , or
The angles of a triangle sum to , and so, we get:
V + V = 180
2V = 180
V, or vertex angle measures: , or
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