SOLUTION: Show that the point (6,6),(2,3) and (4,7) are the vertices of a right angled triangle

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Question 1009174: Show that the point (6,6),(2,3) and (4,7) are the vertices of a right angled triangle
Found 2 solutions by jim_thompson5910, ikleyn:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let

P = (6,6)
Q = (2,3)
R = (4,7)

Find the slope of segment PQ to get


Find the slope of segment PR to get


Find the slope of segment QR to get


-------------------------------------------

Multiply the slopes of PR and QR to get

(slope of PR)*(slope of QR) = (-1/2)*(2) = -1

Since the product of the two slopes is -1, this means that segment PR and segment QR are perpendicular. We have a right angle form at where the segments meet (at point R)

So we definitely have a right triangle.

Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.
Show that the point (6,6), (2,3) and (4,7) are the vertices of a right angled triangle.
----------------------------------------------------------------------
Calculate the three segments in the coordinate plane that are sides of the triangle.

For example, one segment, connecting the points (6,6) and (2,3), is (6-2,6-3) = (4,3).
Its length is  =  = 5.

Two other segments are (2,-1) and (2,4).
Their lengths are  =  and  = .

Now notice that  = 25 and  +  = 5 + 20 = 25.

It is just enough to state that the triangle is right-angled.
The point (4,7) is the vertex of the right angle.


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