SOLUTION: in a triangle ABC, XY is parallel to BC ;AX=9cm , XB=4.5cm and BC =18cm find : (i) AY/YC (ĦĦ)YC/AC (ĦĦĦ)XY

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Question 1006050: in a triangle ABC, XY is parallel to BC ;AX=9cm , XB=4.5cm and BC =18cm find : (i) AY/YC
(ĦĦ)YC/AC
(ĦĦĦ)XY
Answer by dkppathak(439)   (Show Source): You can put this solution on YOUR website!
in a triangle ABC, XY is parallel to BC ;AX=9cm , XB=4.5cm and BC =18cm find : (i) AY/YC
(ĦĦ)YC/AC
(ĦĦĦ)XY
solution
By Basic proportion theorem (BPT)
AX/XB=AY/YC
9/4.5=AY/YC
2/1=Ay/YC
(ii)yc/AC=XB/AB corollary BPT
YC/AC=4.5/13.5
YC/AC=1/3
(iii)Ax/AB=XY/BC corollary BPT
9/13.5=xy/BC
2/3=XY/18
3XY=36
XY=12
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