# SOLUTION: In &#916;ABC, the measure of A is 17° more than four times the measure of B. The measure of C is 5° less than the measure of B. Find the measure of each angle of the triangle.

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 Question 648185: In ΔABC, the measure of A is 17° more than four times the measure of B. The measure of C is 5° less than the measure of B. Find the measure of each angle of the triangle.Answer by shweta(56)   (Show Source): You can put this solution on YOUR website!Given: In triangle ABC, Bis measure of Angle B,A is the measure of Angle A and C of Angle C Angle A= 17+4B ......(1) Angle C= B-5 ......(2) Sum of all the angles of the triangle ABCis 180 degree Angle A+Angle B+ Angle C= 180 ....(3) Substitute the value of A and C in equation 3 17+4B+B+B-5=180 6B+12=180 6B=180-12 6B=168 B=168/6 Angle B=28 degree Substitute the value of B in equation 1 A=17+4B A=17+4*28 A=17+112 Angle A=129 degree Now substitute the value of B in equation 2 to find the value of Angle C Angle C= B-5 Angle C= 28-5 Angle C= 23 degree CHECK: You can check your answer by putting in the value of all the angles in equation 3 and see if the sum is 180 degree Angle A+Angle B+Angle C=180 129+28+23=180 Hence our answer is correct