# SOLUTION: Here is my problem: A piece of art is in the shape of an equilateral triangle with the sides of 7 in. Find the area of the piece of art. Round your answer to the nearest tenth.

Algebra ->  -> SOLUTION: Here is my problem: A piece of art is in the shape of an equilateral triangle with the sides of 7 in. Find the area of the piece of art. Round your answer to the nearest tenth.       Log On

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 Question 409603: Here is my problem: A piece of art is in the shape of an equilateral triangle with the sides of 7 in. Find the area of the piece of art. Round your answer to the nearest tenth. Answer by nerdybill(7090)   (Show Source): You can put this solution on YOUR website!A piece of art is in the shape of an equilateral triangle with the sides of 7 in. Find the area of the piece of art. Round your answer to the nearest tenth. . The challenge is to find the height. Draw a diagram--it'll help . Let h = height then h^2 + (7/2)^2 = 7^2 h^2 + 49/4 = 49 h^2 = 49 - 49/4 h^2 = 196/4 - 49/4 h^2 = 147/4 h = sqrt(147)/2 . area then is (1/2)base*height (1/2)(7)(sqrt(147)/2) (7/4)sqrt(147) 21.2 square inches