Questions on Geometry: Triangles answered by real tutors!

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Question 168613: "the area in square meters for a triangular sail is given by A(x)=x^2+5x+6": "the area in square meters for a triangular sail is given by A(x)=x^2+5x+6"
Answer by midwood_trail(231) About Me  (Show Source):
You can put this solution on YOUR website!
This question is not complete.
Retype your question in full.

Question 168336This question is from textbook Geometry
: I have triangle PQR. It is an isosceles triangle. Angles R and Q are congruent. Measure of segment PQ is the square root of x+3. Measure of segment PR is x+1. What does x equal and what is the measurement of PR?This question is from textbook Geometry
: I have triangle PQR. It is an isosceles triangle. Angles R and Q are congruent. Measure of segment PQ is the square root of x+3. Measure of segment PR is x+1. What does x equal and what is the measurement of PR?
Answer by Mathtut(373) About Me  (Show Source):
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with the givens we know that PQ = PR, because sides opposite congruent angles are equal.
x+1=sqrt(x+3) now square both sides and we will eliminate the squareroot
(x+1)^2=x+3
x^2+2x+2=x+3
x^2+x-2=0now factor
(x+2)(x-1)=0
so x=1 and -2...throw out the negative value
and x=1 and PR=2

Question 168324This question is from textbook Geometry
: I have triangle PQR. It is an isosceles triangle. Angles R and Q are congruent. Measure of segment PQ is the square root of x+3. Measure of segment PR is x+1. What does x equal and what is the measurement of PR?This question is from textbook Geometry
: I have triangle PQR. It is an isosceles triangle. Angles R and Q are congruent. Measure of segment PQ is the square root of x+3. Measure of segment PR is x+1. What does x equal and what is the measurement of PR?
Answer by Mathtut(373) About Me  (Show Source):
You can put this solution on YOUR website!
with the givens we know that PQ = PR, because sides opposite congruent angles are equal.
x+1=sqrt(x+3) now square both sides and we will eliminate the squareroot
(x+1)^2=x+3
x^2+2x+2=x+3
x^2+x-2=0now factor
(x+2)(x-1)=0
so x=1 and -2...throw out the negative value
and x=1 and PR=2

Question 168206This question is from textbook
: Please help me solve this: Find the formula for the area of an isosceles right triangle in terms of the hypotenuse?
all i know is that A=1/2bh... but i do not know what to do with it. Thank you in advance!
This question is from textbook
: Please help me solve this: Find the formula for the area of an isosceles right triangle in terms of the hypotenuse?
all i know is that A=1/2bh... but i do not know what to do with it. Thank you in advance!

Answer by Earlsdon(3719) About Me  (Show Source):
You can put this solution on YOUR website!
First, to draw an isosceles right triangle, draw a square, then draw one of its diagonals. You now have two congruent isosceles right triangles.
Now draw the other diagonal and you will see that the diagonals of a square bisect each other.
Next, erase one of the triangles (that's half the square) and you are left with one isosceles right triangle whose height (h) is exactly half the length of its base (b). But the base is really the hypotenuse of this right triangle. So, for the area of this triangle, you can write:
A = (1/2)bh But h = (1/2)b, so substitute this to get:
A = (1/2)b*(1/2)b Simplify.
A = (1/4)b^2 where b is the length of the hypotenuse.

Question 167860: I have a triangle where the angles are given as 46 degrees, x and y. The sides adjacent to y are equal to each other. I am asked to solve for angles x and y. Thank you.: I have a triangle where the angles are given as 46 degrees, x and y. The sides adjacent to y are equal to each other. I am asked to solve for angles x and y. Thank you.
Answer by ankor@dixie-net.com(4503) About Me  (Show Source):
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I have a triangle where the angles are given as 46 degrees, x and y. The sides adjacent to y are equal to each other. I am asked to solve for angles x and y
:
I can't believe how I screwed this one up, it should be:
:
If the sides adjacent to y are equal, it's an isoceles triangle; therefore
angles 46 and x are equal:
x = 46 degrees also
y = 180 - 46 - 46
y = 88 degrees
:
I am sorry! Carl

Question 167950This question is from textbook mathematical ideas
: why must the sum of two sides of a triangle always be greater than the third side.This question is from textbook mathematical ideas
: why must the sum of two sides of a triangle always be greater than the third side.
Answer by Edwin McCravy(2043) About Me  (Show Source):
You can put this solution on YOUR website!
why must the sum of two sides of a triangle always be greater than the third side.

Because the shortest distance between two points 
is the line segment joining them.


drawing(400,400,-4,4,-4,4, triangle(-1,-2,1,3,3,-3),
locate(-1.2,-2,A),locate(1,3.3,B),locate(3,-3,C) 


)

The shortest distance from point A to point B 
is the segment AB. So it certainly farther to go 
from A to B by going to C first and then from C to B.

Edwin

Question 167885: if the area of a triangle is 60 sq m and the base is 20 m, what is the altitude h. ISBN 0-13-073784-4: if the area of a triangle is 60 sq m and the base is 20 m, what is the altitude h. ISBN 0-13-073784-4
Answer by nerdybill(1049) About Me  (Show Source):
You can put this solution on YOUR website!
if the area of a triangle is 60 sq m and the base is 20 m, what is the altitude h.
.
For any triangle,
area = (1/2)bh
where
b is length of base
h is height
.
Plug in what was given into:
area = (1/2)bh
60 = (1/2)(20)h
solve for h:
60 = (1/2)(20)h
60 = (10)h
6 m = h (altitude)

Question 167677: Find the values of the variables:
one angle = 90 degrees
one angle = (2x-11)
one angle = (y+16)
two congruent sides are of the right angle
(2x-11)+(y+16) = 90
: Find the values of the variables:
one angle = 90 degrees
one angle = (2x-11)
one angle = (y+16)
two congruent sides are of the right angle
(2x-11)+(y+16) = 90

Answer by nerdybill(1049) About Me  (Show Source):
You can put this solution on YOUR website!
Find the values of the variables:
one angle = 90 degrees
one angle = (2x-11)
one angle = (y+16)
.
Since you have two unknowns (x and y), you'll need two equations.
.
equation 1: (as you say)
(2x-11)+(y+16) = 90
.
since there are two congruent sides:
equation 2:
(2x-11)=(y+16)
.
Solve equation 2 for x:
(2x-11)=(y+16)
2x-11 = y+16
2x = y+27
x = (1/2)(y+27)
.
Plug the above into equation 1 and solve for y:
(2x-11)+(y+16) = 90
(2(1/2)(y+27)-11)+(y+16) = 90
y+27-11+y+16 = 90
2y+27-11+16 = 90
2y+16+16 = 90
2y+32 = 90
2y = 58
y = 29
.
Plug it back into equation 2 to find x:
(2x-11)=(y+16)
(2x-11)=(29+16)
2x-11=45
2x=56
x = 28
.
solution:
x is 28
y is 29



Question 167531This question is from textbook glencoe Mathmatics Geometry
: Find x,JM,MN,and JN if triangle JMN is an isosceles triangle with line JM congruent to line MN.
JM=2X-5
MN=3x-9
JN=x-2
T.he book answer is x=4,JM=3,MN=3,JN=2
Please explain how to work
This question is from textbook glencoe Mathmatics Geometry
: Find x,JM,MN,and JN if triangle JMN is an isosceles triangle with line JM congruent to line MN.
JM=2X-5
MN=3x-9
JN=x-2
T.he book answer is x=4,JM=3,MN=3,JN=2
Please explain how to work

Answer by checkley77(3412) About Me  (Show Source):
You can put this solution on YOUR website!
JM=MN
JM=2X-5
MN=3x-9
JN=x-2
Thus: 2x-5=3x-9
2x-3x=-9+5
-x=-4
x=4 answer.
2*4-5=8-5=3 for JM.
3*4-9=12-9=3 for MN.
4-2=2 for JN.


Question 166330: Find the value of x and then classify the triangles. pg. 174
20x+10, 30x -2, 7x+1
I was thinking that I had to add
20x+30x+7x= 57x
Then
10-2+1=9
57x+9=360
57x=351
It is just not coming out right. So frustrated!
: Find the value of x and then classify the triangles. pg. 174
20x+10, 30x -2, 7x+1
I was thinking that I had to add
20x+30x+7x= 57x
Then
10-2+1=9
57x+9=360
57x=351
It is just not coming out right. So frustrated!

Answer by jim_thompson5910(9217) About Me  (Show Source):
You can put this solution on YOUR website!
Its hard to know what you are doing without the full instructions and what "20x+10, 30x -2, 7x+1 " are referring to (are these side lengths? angles?)

However, since I'm seeing a "360" I'm assuming that you are working with angles.

There's a problem though: ALL angles in a triangle add to 180 degrees (not 360 degrees). So the equation should be:


(20x+10)+(30x -2)+(7x+1)=180


Let me know if you still need help.


Note: the answer is x=3 and the three angles are 70, 88, and 22

Question 166087This question is from textbook Heart of Mathmatics
: If a natural number is written as the sum of three natural numbers, show that one of the numbers in the sum must be less than or equal to one third of the original natural number.This question is from textbook Heart of Mathmatics
: If a natural number is written as the sum of three natural numbers, show that one of the numbers in the sum must be less than or equal to one third of the original natural number.
Answer by stanbon(18788) About Me  (Show Source):
You can put this solution on YOUR website!
On second thought:
If the natural number is a multiple of three, it can be written
as a sum of three numbers, each of which is one-third the original
number. If that sum is not used, one of the numbers in the sum
must be less than one-third the original number.
------------
If the natural number is not a multiple of three, at least one
of the numbers in the sum must be less than one-third the original
number.
------------
Stan H.
Cheers,

Question 165934: The legs of a right triangle differ by 2 centimeters and the hypotenuse is 4 centimeters more than the shorter leg. Find the sides of the triangle.: The legs of a right triangle differ by 2 centimeters and the hypotenuse is 4 centimeters more than the shorter leg. Find the sides of the triangle.
Answer by jojo14344(832) About Me  (Show Source):
You can put this solution on YOUR website!
shorter_leg=x ---> let's point it as the adjacent side
x+2 -------------> let's point it as the oppposite side
x+4 -------------> hypotenuse side
differ by 2cm --system(x=adj,x+2=opp)
By Pyth. Theorem:
(x+4)^2=x^2+(x+2)^2
x^2+8x+16=x^2+x^2+4x+4
2x^2+4x+4-x^2-8x-16=0
x^2-4x-12=0, perfect square, factorable
(x-6)(x+2)=0
2 values ---system(highlight(x=6),x=-2)
As highlighted, shortest side: adj= 6cm; opp=6+2=8cm; hyp=6+4=10cm
See below,
drawing(300,300,-5,10,-5,10,graph(300,300,-5,10,-5,10),(green(line(6,0,0,0))),(blue(line(6,0,6,8))),(red(line(6,8,0,0)))) system(green=adjacent=6cm,blue=opposite=8cm,red=hypotenuse=10cm)
check:
10^2=6^2+8^2
100=36+64
100=100
Thank you,
Jojo

Question 165697: Triangle ABC is isoceles with ABis equal to AC 7.5cm and BC is 9cm. The height AD from A to BC , is 6cm. Find the area of triangle ABC. What will the height be from C to AB i.e CE : Triangle ABC is isoceles with ABis equal to AC 7.5cm and BC is 9cm. The height AD from A to BC , is 6cm. Find the area of triangle ABC. What will the height be from C to AB i.e CE
Answer by jojo14344(832) About Me  (Show Source):
You can put this solution on YOUR website!

I'll leave the sketch with you okay, & hopefully we can follow together:
We find first the Area=(1/2)bh
where, BC=base=9cm, & AD=height=6cm
So, A=(1/2)(9)(6)
A=27cm^2
Now , next is interesting in finding CE?
We first get angle(B) by trigo function of right triangle. How?
Since AD split the base(BC) in to half, side(BD)=9/2=4.5cm right? Same as side(DC).
That forms a right triangle (ADB).
sin(beta)=opp/hyp=AD/AB=6/7.5=0.80
(beta)=sin^-1(0.80)
highlight((beta)=53.13^o)
.
Now we know line CE(?) cuts line AB into half:7.5/2=3.75cm=BE, right?
That forms a triangle BCE and we'll use Cosine Law in getting line CE.
c^2=a^2+b^2-2abcos(beta)
where ---system(a=BC=9cm,b=BE=3.75cm,c=CE)
Continuing,
c^2=9^2+3.75^2-2(9)(3.75)cos(53.13)
c^2=81+14.0625-40.50=95.0625-40.50
c=sqrt(54.5625)
highlight(c=7.38cm=CE)
Thank you,
Jojo


Question 165593: Hi, if theta is an acute angle and sin theta =1/2, then cos theta=
I have drawn a right triangle with the hypotenus on the right. It has a one on the bottom and a two on the hypotenuse. Then I tried 1^2+b^2=2^2 and ended up with square root of b^2 =square root of 3. I do not know where to go from there

Thankyou.
: Hi, if theta is an acute angle and sin theta =1/2, then cos theta=
I have drawn a right triangle with the hypotenus on the right. It has a one on the bottom and a two on the hypotenuse. Then I tried 1^2+b^2=2^2 and ended up with square root of b^2 =square root of 3. I do not know where to go from there

Thankyou.

Answer by Earlsdon(3719) About Me  (Show Source):
You can put this solution on YOUR website!
You have done ok so far!
In your triangle, you have a = 1, c = 2, and b = sqrt(3).
To see how we get b, you have:
b^2 = 3 Take the square root of both sides.
b = sqrt(3)
The sin of theta (I'll call it A because I can't do a theta symbol) is given as 1/2 because the sine of the angle is the side opposite the angle (a = 1) over the hypotenuse (c = 2), so you get sin(A) = 1/2
The cosine of this angle (A) is the side adjacent to the angle (b = sqrt(3) over the hypotenuse (c = 2), so...
cosin(A) = sqrt(3)/2

Question 165242: Given:Triangle ABC
Segment BD is perpindicular to segment AC
Segment BD is a median of Triangle ABC
Find: What kind of triangle is Triange ABC?
: Given:Triangle ABC
Segment BD is perpindicular to segment AC
Segment BD is a median of Triangle ABC
Find: What kind of triangle is Triange ABC?

Answer by midwood_trail(231) About Me  (Show Source):
You can put this solution on YOUR website!
Given:Triangle ABC
Segment BD is perpendicular to segment AC
Segment BD is a median of Triangle ABC
What kind of triangle is Triange ABC?
BD is perpendicular to AC. This means that angle D is 90 degrees.
Two triangles are formed: Triangle ABD and Triangle CBD.
BD is also a median. This means that it divides AC into two equal parts.
From the given data, I gather that AB = BC but also that AB and BC do not equal AC.
I think this is an isosceles triangle.

Question 165224This question is from textbook Lets Review Math A
: QUESTION: In isosceles triangle ABC the ratio of the measure of vertex angle A to the measure of angle B is 2 to 5. Find angle C.

1st APPROACH: we know that in an isosceles triangle two angles are the same and the sides opposite them are also the same.

Since this problem doesn't tell you which is the base vertex in this isosceles triangle, I have assumed it to be 5x. Because of "RULE:"
the length of each side is less than the sum of the lengths of the other two sides and greater than the difference between these lengths....3less than x less than 7. Therefore x is in the range of 4, 5, 6.

2x+5x+5x=180

12x=180

x=15
Angle C is 75 degrees


2nd APPROACH: we know that in an isosceles triangle two angles are the same and the sides opposite them are also the same.


Since we already used 5x as the base vertex in our previous approach lets assume 2x is the base angle, this time, because it's an isosceles triangle.


2x+2x+5x=180

9x=180

x=20
Angle C is 40 degrees


BOOKS ANSWER IS 100 degrees, why?
This question is from textbook Lets Review Math A
: QUESTION: In isosceles triangle ABC the ratio of the measure of vertex angle A to the measure of angle B is 2 to 5. Find angle C.

1st APPROACH: we know that in an isosceles triangle two angles are the same and the sides opposite them are also the same.

Since this problem doesn't tell you which is the base vertex in this isosceles triangle, I have assumed it to be 5x. Because of "RULE:"
the length of each side is less than the sum of the lengths of the other two sides and greater than the difference between these lengths....3less than x less than 7. Therefore x is in the range of 4, 5, 6.

2x+5x+5x=180

12x=180

x=15
Angle C is 75 degrees


2nd APPROACH: we know that in an isosceles triangle two angles are the same and the sides opposite them are also the same.


Since we already used 5x as the base vertex in our previous approach lets assume 2x is the base angle, this time, because it's an isosceles triangle.


2x+2x+5x=180

9x=180

x=20
Angle C is 40 degrees


BOOKS ANSWER IS 100 degrees, why?

Answer by jim_thompson5910(9217) About Me  (Show Source):
You can put this solution on YOUR website!
Here's a quick note about what the ratio is really saying:

Since the ratio is vertex angle A to the measure of angle B, this means that we have this ratio:

A:B ---> 2:5

So this means that the vertex angle is SMALLER than the base angle. However, if you have a base angle of 40 degrees, this means that the vertex angle is 180-2*40=180-80=100 which means that the vertex angle is larger (not smaller) than the base angle. So this effectively rules out the "2nd Approach" answer. Remember, the ratio is vertex:base angle (not the other way around)


However, I agree with your first approach. That answer is correct. You'll find that the base angles are 75 degrees and the vertex angle is 30 degrees. Since the ratio of 30:75 reduces to 2:5, this verifies the answer.


Note: it is IMPOSSIBLE to have both an isosceles triangle AND have a base angle that is greater than 90 degrees. Why? Base angles are equal. So if there is an obtuse base angle, there are really 2 obtuse angles in the triangle (which is impossible; triangles can only have at most one obtuse angles). So this means that either the book is wrong or maybe you read the wrong answer.

Question 165226This question is from textbook Lets Review Math A
: QUESTION: Vertex angle A of isosceles triangle ABC measures 20 degrees more than three times measure angle B. Find measure angle C.


Approach:


(3x+20)+x+x=180


5x=180


x=32
BOOKS ANSWER IS 34. WHY???
This question is from textbook Lets Review Math A
: QUESTION: Vertex angle A of isosceles triangle ABC measures 20 degrees more than three times measure angle B. Find measure angle C.


Approach:


(3x+20)+x+x=180


5x=180


x=32
BOOKS ANSWER IS 34. WHY???

Answer by edjones(2391) About Me  (Show Source):
You can put this solution on YOUR website!
32 is correct.

Question 164928: A rectangular piece of cardboard with perimeter 30 in., two parallel and equally spaced creases are made. The cardboard is then folded to make a prism with open ends that are equilateral triangles. Find the volume of the prism as a function of x and what is the domain of V(x)? Thanks to those who can help!: A rectangular piece of cardboard with perimeter 30 in., two parallel and equally spaced creases are made. The cardboard is then folded to make a prism with open ends that are equilateral triangles. Find the volume of the prism as a function of x and what is the domain of V(x)? Thanks to those who can help!
Answer by ankor@dixie-net.com(4503) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangular piece of cardboard with perimeter 30 in., two parallel and equally spaced creases are made. The cardboard is then folded to make a prism with open ends that are equilateral triangles. Find the volume of the prism as a function of x and what is the domain of V(x)?
:
Let x = the 3 equal distances, between the two folds
then
3x = width of the cardboard
and
Let L = the length of cardboard
;
Perimeter:
2(3x) + 2L = 30
Simplify divide by 2
3x + L = 15
L = (15-3x)
:
Find the height (h) of the equilateral triangle with sides = x
h^2 + (x/2)^2 = x^2
h^2 = x^2 - (x/2)^2
h = sqrt(x^2-(x/2)^2)
:
Vol of a triangular prism = 1/2*L*w*h
In this problems
L = (15-3x)
w = x
h = sqrt(x^2-(x/2)^2)
:
V(x) = 1/2*(15-3x)*x*sqrt(x^2-(x/2)^2)
:
You can tell by L, (15-3x), that x has to be less than 5 (the domain)
:
If you graph this:
 graph( 300, 200, -3, 6, -10, 25, .5*(15-3x)*x*sqrt(x^2-(x/2)^2))
The max volume when x = 3.33, Domain 0 to <+5

Question 164675: Find the following. Assume that variables can represent any real numbers.
sqrt(a+5)^2
: Find the following. Assume that variables can represent any real numbers.
sqrt(a+5)^2

Answer by checkley77(3412) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt(a+5)^2=a+5 answer.

Question 164661: 65)



subtract the polynomials
(-6s^2 +5s+4)-(7s^2+4)
: 65)



subtract the polynomials
(-6s^2 +5s+4)-(7s^2+4)

Answer by Fombitz(1744) About Me  (Show Source):

Question 164657: :
Answer by Alan3354(1218) About Me  (Show Source):
You can put this solution on YOUR website!
There are 2 possibilities.
If c is the hypotenuse, the 3rd side is 5 (sqrt(c^2 - b^2)).
The 3rd side could be sqrt(c^2 + b^2), or sqrt(33), too.

Question 164631This question is from textbook Geometry concepts and skills
: Suppose triangle LWT is isosceles, the measure of angle W= 90 degrees, LW= 7X+ 21, and TW= 4X + 21.
a. Determine LW,TW,LT, the measure of angle L and angle T.
from: geometry
concepts and skills
Chapter 4 Section 7
This question is from textbook Geometry concepts and skills
: Suppose triangle LWT is isosceles, the measure of angle W= 90 degrees, LW= 7X+ 21, and TW= 4X + 21.
a. Determine LW,TW,LT, the measure of angle L and angle T.
from: geometry
concepts and skills
Chapter 4 Section 7

Answer by scott8148(2724) About Me  (Show Source):
You can put this solution on YOUR website!
isosceles means that the two base angles are equal as are the sides opposite the angles

LW=TW __ 7X+21=4X+21 __ subtracting 4x+21 __ 3X=0 __ X=0

LW=TW=21

there are 180º in a triangle __ the vertex angle is 90º, so the sum of the two base angles is also 90º
__ so each bse angle equals 45º

by Pythagoras __ LT^2=LW^2+TW^2 __ LT^2=2(21^2) __ LT=21*sqrt(2)

Question 164522: The longest side of a right triangle is 5 meters, and the shortest side is 3 meters. What is the area of the triangle in square meters?: The longest side of a right triangle is 5 meters, and the shortest side is 3 meters. What is the area of the triangle in square meters?
Answer by orca(336) About Me  (Show Source):
You can put this solution on YOUR website!
As the hypotenuse is the longest side of a right triangle, so
the hypotenuse c = 5.
The length of one of its leg is a = 3
So the length of the other leg is
b = sqrt(5^2-3^2)=4
Thus the area = (1/2)ab =(1/2)*3*4=6 m^2

Question 164500: A=1/2 bh for h
solve the equation
the largest angle in a triangle is 3 more than 4 times as big as the smallest angle. The middle angle is 2 less than twice the smallest. What is the measure of the largest angle?
: A=1/2 bh for h
solve the equation
the largest angle in a triangle is 3 more than 4 times as big as the smallest angle. The middle angle is 2 less than twice the smallest. What is the measure of the largest angle?

Answer by midwood_trail(231) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the equation.
Solve for h.
A = 1/2 (bh)
We can write 1/2 (bh) like bh/2 for easy reading. They both mean the same thing.
We now have A = bh/2
Multiplying both sides of the equation by 2 and we get:
2A = bh
To solve the equation for h, we want to get h alone.
To do so, divide both sides of the equation by b.
2A/b = h

Did you follow?

Question 164545This question is from textbook Connected Mathematics
: how do i get the two coordinets
This question is from textbook Connected Mathematics
: how do i get the two coordinets

Answer by midwood_trail(231) About Me  (Show Source):
You can put this solution on YOUR website!
Do you have a sample question related to coordinates?
Post your question in full and then we'll be able to guide you safely through.

Question 164474: I am having problems with this question.
If one of the acute angles of a right triangle has twice the measure of the other acute angle, what is the measure of the acute angle with the greater measure?
: I am having problems with this question.
If one of the acute angles of a right triangle has twice the measure of the other acute angle, what is the measure of the acute angle with the greater measure?

Answer by Fombitz(1744) About Me  (Show Source):
You can put this solution on YOUR website!
Let's call the two angles A and B.
1.A=2B
You also know that
A+B+90=180
A+B=90
Use eq. 1 and substitute into this equation,
A+B=90
(2B)+B=90
3B=90
B=30
A=60
The acute angle with the greater measure is 60 degrees.

Question 164343: http://davinci.keymath.com/KeyPressPortalV2.0/ImportingCourses/DG4E/chapter4/Images/203-01.gif
bottom image on right find angle measures of r, s, and u
i believe
m=30
n=50
p=82
q=28
t=118
: http://davinci.keymath.com/KeyPressPortalV2.0/ImportingCourses/DG4E/chapter4/Images/203-01.gif
bottom image on right find angle measures of r, s, and u
i believe
m=30
n=50
p=82
q=28
t=118

Answer by nerdybill(1049) About Me  (Show Source):
You can put this solution on YOUR website!
I agree with your answers.

Question 163952: What is values of x, x + 1, and x + 2 =12?
Thanks in advance!
: What is values of x, x + 1, and x + 2 =12?
Thanks in advance!

Answer by gonzo(444) About Me  (Show Source):
You can put this solution on YOUR website!
x + x + 1 + x + 2 = 12
3x +3 = 12
3x = 9
x = 3
x+1 = 4
x+2 = 5

Question 163954: Can you please help me solve this problem?
-3 - 4 (t-5) = -2(t+3) + 11
: Can you please help me solve this problem?
-3 - 4 (t-5) = -2(t+3) + 11

Answer by gonzo(444) About Me  (Show Source):
You can put this solution on YOUR website!
if i understand this correctly, it is
-3 - 4(t-5) = -2(t+3) + 11
there are different ways to approach it, but this way works on this equation.
-----
first multiply out to remove the parentheses.
-3 -4t + 20 = -2t - 6 + 11
combine like terms.
-4t + 17 = -2t + 5
add 4t to both sides of the equation.
17 = 2t + 5
subtract 5 from both sides of the equation.
12 = 2t
divide both sides of the equation by 2.
t = 6
-----
to prove, substitute in original equation
-----
-3 - 4(6-5) = -2(6+3) + 11
simplify expressions within parentheses.
-3 -4(1) = -2(9) + 11
perform operations to remove parentheses.
-3 -4 = -18 + 11
combine like terms
-7 = -7
-----
answer is proven correct.
answer is t = 6
-----

Question 163919: smithville is 70 miles from johnstown and tomstown is 90 miles from johnstown, which is a possible distance? A. 200 B. 150 C. 10 or D. 5
This is not a text book question... something doesn't seem right...wondering if numbers were misprinted. Thank you!
: smithville is 70 miles from johnstown and tomstown is 90 miles from johnstown, which is a possible distance? A. 200 B. 150 C. 10 or D. 5
This is not a text book question... something doesn't seem right...wondering if numbers were misprinted. Thank you!

Answer by scott8148(2724) About Me  (Show Source):
You can put this solution on YOUR website!
picture johnstown as the center of a circle

smithville is on a circle with a 70 mi radius and tomstown is on a circle with a 90 mi radius

if they are on the same side of the circles (in the same direction from johnstown)
__ the closest they can be is 20 mi (90-70)

if they are on opposite sides of the circles (opposite directions from johnstown)
__ the farthest apart they can be is 160 mi (90+70)

there is only one answer between 20 and 160

Question 163012: how do i determine which angle is greater in a triangle??...: how do i determine which angle is greater in a triangle??...
Answer by elima(1420) About Me  (Show Source):
You can put this solution on YOUR website!
It's hard to answer without an example to work with. Why don't you post a problem, and maybe we can help you with that.
:)

Question 163039: Triangle EFG is isosceles with base FG. K is the midpoint of FE and L is the midpointbetween EG. Do not use the distance formula. No ordered pairs are given. Draw and label this triangle.
EK=2x+3 LG=5x-9 FG=4x (These are not equations.)
What is the value of x?
Find the perimeter of thiangle EFG.
Find the area of the triangle using Pythagoras. round to nearest whole number.
Find the area of the triangle using Hero's formula. Round to nearest whole number.
How do they compare?
: Triangle EFG is isosceles with base FG. K is the midpoint of FE and L is the midpointbetween EG. Do not use the distance formula. No ordered pairs are given. Draw and label this triangle.
EK=2x+3 LG=5x-9 FG=4x (These are not equations.)
What is the value of x?
Find the perimeter of thiangle EFG.
Find the area of the triangle using Pythagoras. round to nearest whole number.
Find the area of the triangle using Hero's formula. Round to nearest whole number.
How do they compare?

Answer by joecbaseball(34) About Me  (Show Source):
You can put this solution on YOUR website!
Okay, here we go. Not a difficult problem, but it comes in five parts. Here we go…
First of all, you must draw your picture correctly according to the description:
First, draw an isosceles triangle, but don’t worry about the dimensions, as long as you determine which side is the base. Now label it correctly. You have the base on the bottom, labeled F and G.
The top of the triangle is E. Now you are given the two midpoints of the sides. Now, a midpoint divides the side in question into two equal parts, and since this is an isosceles triangle, both of the sides of the triangle (EF and EG) are equal, and thus, since each of two equal sides are cut exactly in half, each of those 4 segments are equal. Now we can answer the first part:
WHAT IS THE VALUE OF x?
Since each of the four segments are equal, and the lengths of two of them are given (2x+3 and 5x-9), we can set these equal to each other to solve for x:
So, 2x+3 = 5x-9. Solving for x gives you that x=4. That is the answer to the first question.
FIND THE PERIMETER OF TRIANGLE EFG.
Since we now know that x=4, then the lengths of each of the side segments is 11, and thus each of the equal sides of the isosceles triangle is 22. You’re also given that the base is equal to 4x, and since we know that x=4, we know that the base is 16. Since the perimeter of a triangle (or any figure) is the sum of the sides, then the perimeter of this triangle is 22 + 22 + 16, or 60.
FIND THE AREA OF THE TRIANGLE USING PYTHAGORAS. ROUND TO THE NEAREST WHOLE NUMBER.
The Pythagorean theorem says that, in a right triangle, the square of the hypoteneuse is equal to the sum of the squares of the other two sides.
Thus, we have to find the height. The math to prove this is too long to show here, but suffice to say that the line dropped from the vertex of the third angle of an isosceles triangle does a few things. It bisects that angle, it forms a right angle with the base, and it bisects the base. Since it bisects the base, and we know that the base = 16, each side of the base on either side of the right angle = 8. We then now know two of the three sides of the right triangle. The hypoteneuse is 22, the base is 8, and, thus, we can compute the value of the third side, which is the height of the big triangle.
So, we have that 8^2 + x^2 = 22^2.
This gives us 64 + x^2 = 484. Subtract 64 from both sides, and this gives us:
x^2 = 420. Now take the square root of both sides and this gives us that:
x = 20.49.
Now we have the base and the height forming a right angle with the base. We can then use the formula to find the AREA of the triangle using the formula:
AREA = ½ (BASE)(HEIGHT):
AREA = ½ (16)(20.49) = 163.95 = 164 (the answer was asked to be rounded to the whole number).
FIND THE AREA OF THE TRIANGLE USING HERO’S FORMULA
Hero’s formula says that if S = (the sum of the sides of the triangle) divided by 2, then the AREA of the triangle can be given by:
AREA = the square root of [S (S – side one)(S – side 2)(S – side 3)]
So, in this case, S = (22 + 22 + 16)/2, which is 60/2, or 30.
Thus the AREA = the square root of [30(30 – 22)(30 – 22)(30 – 16)], which is sqrt[30(8)(8)(14)], which is sqrt[26880], which is 163.95 = 164 (the answer was asked to be rounded to the whole number).
HOW DO THEY COMPARE?
They are the same.
WHEW !!! Hope that this helps. Good luck !

Question 162937: In an isosceles triangle, the length of one of the equal sides is three time the length of the third side. The perimeter is 21 meters. Find the length of each side.: In an isosceles triangle, the length of one of the equal sides is three time the length of the third side. The perimeter is 21 meters. Find the length of each side.
Answer by checkley77(3412) About Me  (Show Source):
You can put this solution on YOUR website!
3s+3s+s=21
7s=21
s=3 For the third short side.
3*3=9 for the equal sides.
Proof:
9+9+3=21
21=21

Question 162702: if you know the area of a triangle = 60 sq feet and the base is 6ft, what's the height?: if you know the area of a triangle = 60 sq feet and the base is 6ft, what's the height?
Answer by nerdybill(1049) About Me  (Show Source):
You can put this solution on YOUR website!
if you know the area of a triangle = 60 sq feet and the base is 6ft, what's the height?
.
Because the area of ANY triangle is:
A=(1/2)BH
where
A is the area
B is length of the base
H is the height
.
Plugging in what we know:
60 = (1/2)(6)H
Solving for H, start by multiplying both sides by 2:
120 = 6H
Dividing both sides by 6:
20 feet = H (height of triangle)

Question 162498: I'm lost
In a right triangle ABC, angle B=90, AB=5, and AC=12. Find BC. Round to the nearest tenth if necessary. Must show work.
Please Help
Thanks
: I'm lost
In a right triangle ABC, angle B=90, AB=5, and AC=12. Find BC. Round to the nearest tenth if necessary. Must show work.
Please Help
Thanks

Answer by elima(1420) About Me  (Show Source):
You can put this solution on YOUR website!
You use the Pythagorean theorem to solve.
a^2 +b^2= c^2
a=5
c= 12
5^2 + bc^2 = 12^2
25 + bc^2 = 144
b^2 = 119
take the square root of both sides;
bc = 10.91
:)

Question 162499: Find the measure of the hypotenuse of a 30-60-90 triangle whose longer leg has a measure of 6 meters. Give the answer in simplified radical form. Must show work and don't understand how to do this.. Please help.
Thanks
: Find the measure of the hypotenuse of a 30-60-90 triangle whose longer leg has a measure of 6 meters. Give the answer in simplified radical form. Must show work and don't understand how to do this.. Please help.
Thanks

Answer by vleith(1162) About Me  (Show Source):
You can put this solution on YOUR website!
See this --> http://www.mathopenref.com/triangle306090.html
If the longer leg is 6, that corresponds to the sqrt(3)side
The short leg is 6/sqrt(3)
The hypotenuse is (6*2)/sqrt(3)
(6*2)/sqrt(3)
(12)*sqrt(3)/3
4*sqrt(3)


Question 162273: If the base of a larger triangle is 34 inches long, what is the length of side A of the smaller triangle? The smaller triangle's base is 17.. im so not good at math and have been stuck on this for three days someone please help me asap.. this is due later today..: If the base of a larger triangle is 34 inches long, what is the length of side A of the smaller triangle? The smaller triangle's base is 17.. im so not good at math and have been stuck on this for three days someone please help me asap.. this is due later today..
Answer by Alan3354(1218) About Me  (Show Source):
You can put this solution on YOUR website!
If the base of a larger triangle is 34 inches long, what is the length of side A of the smaller triangle? The smaller triangle's base is 17.. im so not good at math and have been stuck on this for three days someone please help me asap.. this is due later today..
-------------------
That's not enough info. All that can be determined from that is that the side A of the smaller is 1/2 that of the larger, but it's necessary to assume they're similar triangles.
Is there additional info, or a drawing?

Question 162200This question is from textbook Geometry
: i need helpThis question is from textbook Geometry
: i need help
Answer by Alan3354(1218) About Me  (Show Source):
You can put this solution on YOUR website!
i need help
--------------
I don't have that book, so I can't help.

Question 161851: angle a is 4 times greater than angle b and angle c is 20 degrees less than angle b...
i have tried every possible whole number and even busted the equation down to as small as 64th increments.we have not yet studied hours,minutes,seconds..
so i figured it was not able to be figured out..could you please help...
thank you..........sherry
: angle a is 4 times greater than angle b and angle c is 20 degrees less than angle b...
i have tried every possible whole number and even busted the equation down to as small as 64th increments.we have not yet studied hours,minutes,seconds..
so i figured it was not able to be figured out..could you please help...
thank you..........sherry

Answer by scott8148(2724) About Me  (Show Source):
You can put this solution on YOUR website!
a+b+c=180

"angle a is 4 times greater than angle b" __ a=4b

"angle c is 20 degrees less than angle b" __ c=b-20

substituting __ (4b)+b+(b-20)=180 __ 6b=200 __ b=100/3

substituting __ a=4(100/3) __ a=400/3

substituting __ c=(100/3)-20 __ c=40/3

Question 161764This question is from textbook Geometry
: the measure of one angle of a triangle is 28 more than the smallest angle of the triangle. the measure of the third angle is twice the measure of the smallest angle. what are all 3 angle measures?
1. Before answering this question, you must know that in any triangle, the sum of all three angles is ALWAYS 180 degrees.
2. You must also know and be able to translate math key words to algebraic form
***is =
***#more than +#
***twice 2*
3. SOLUTION:
let angle x= smallest angle
let angle y= x + 28
let angle z=2x
Since x+(x+28)+(2x)=180 simplify now
4x+28=180
4x+28-28=180-28
4x=152
4x/4=152/4
x=38
smallest angle = 38
angle y=28+x=28+38=66
angle z=2x=2(38)=76
Check 38+66+76=180
This question is from textbook Geometry
: the measure of one angle of a triangle is 28 more than the smallest angle of the triangle. the measure of the third angle is twice the measure of the smallest angle. what are all 3 angle measures?
1. Before answering this question, you must know that in any triangle, the sum of all three angles is ALWAYS 180 degrees.
2. You must also know and be able to translate math key words to algebraic form
***is =
***#more than +#
***twice 2*
3. SOLUTION:
let angle x= smallest angle
let angle y= x + 28
let angle z=2x
Since x+(x+28)+(2x)=180 simplify now
4x+28=180
4x+28-28=180-28
4x=152
4x/4=152/4
x=38
smallest angle = 38
angle y=28+x=28+38=66
angle z=2x=2(38)=76
Check 38+66+76=180

Answer by eperette(63) About Me  (Show Source):

Question 161698: Please help with this problem?
Give the measure in degrees of the angle described
D Angle D represents 1/2 of a complete circle
: Please help with this problem?
Give the measure in degrees of the angle described
D Angle D represents 1/2 of a complete circle

Answer by josmiceli(2024) About Me  (Show Source):
You can put this solution on YOUR website!
A complete circle is 360 degrees
A half-circle is then 180 degrees

Question 161669: Have a right triangle with base h+7 and height of h. The area equals 60. What is the height?: Have a right triangle with base h+7 and height of h. The area equals 60. What is the height?
Answer by gonzo(444) About Me  (Show Source):
You can put this solution on YOUR website!
height = h
base = h+7
area = 60
-----
formula for area = 1/2 base * height
base = h+7
height = h
area = 60
-----
formula becomes
(1/2)*h*(h+7) = 60
multiply both sides by 2 to remove the denominator.
h*(h+7) = 120
multiply out to remove parentheses
h^2 + 7*h = 120
subtract 120 from both sides of equation
h^2 + 7*h - 120 = 0
this is a quadratic equation with factors equal to
(h+15) * (h-8) = 0
-----
h = -15 no good because can't be negative.
answer is
h = 8
h+7 = 15
-----
1/2 base * height should = 60.
1/2 * (15) * (8) = 4 * 15 = 60.
answer is good.
h = 8.

Question 161599: This is a worksheet and we have no book so will you please help.
In triangle XYZ, XY=~YZ. If m angleX=52, find m angle Y. We have to show our work.
Thanks
: This is a worksheet and we have no book so will you please help.
In triangle XYZ, XY=~YZ. If m angleX=52, find m angle Y. We have to show our work.
Thanks

Answer by gonzo(444) About Me  (Show Source):
You can put this solution on YOUR website!
triangle xyz
xy = yz
angle x = 52 degrees.
draw triangle with x on the left, y on top, z on the right.
xy is line going up from left to right.
yz is line going down from left to right.
angle x is the angle in the left hand corner of the triangle.
this is an isosceles triangle because 2 sides are equal (congruent).
in an isosceles triangle the base angles are equal.
these are the angles opposite the equal sides.
angle x is opposite yz
angle z is opposite xy
angle z is therefore equal to angle x is equal to 52 degrees.
since the sum of the interior angles of a triangle is always 180, then angle y must be equal to 180 - angle x - angle z.
this becomes angle y = 180 - 2*52 = 180 - 104 = 76.
angle y must be 76 degrees.
to prove add all 3 angles of the triangle and they must equal 180 degrees.
52 + 52 + 76 = 180.
-----
angle y is 76 degrees.