SOLUTION: xy+xz=2 yx+yz=2 xz+yz=2

SOLUTION: xy+xz=2 yx+yz=2 xz+yz=2

Algebra.Com

Question 97919: xy+xz=2
yx+yz=2
xz+yz=2
Answer by aaaaaaaa(138) (Show Source): You can put this solution on YOUR website!

(with y and z different from 0)
Substitute for y and z in equation 1:

or
x = y = z = +-1
RELATED QUESTIONS
Y is between X and Z. XY=3x+1, YZ=2x-2, and XZ=84. Find YZ. (answered by MathLover1)

Simplify the expression as a single quantity:... (answered by Fombitz)

Given 2^x=3^y=5^z=900^w Show that: xyz=2w(xy+yz+xz) (answered by Edwin McCravy,AnlytcPhil)

XZ=3x, XY=34,... (answered by ikleyn)

is xz+xy = xz+yz and xz+xy = xy + xz both using the commutative property of... (answered by stanbon)

If xy = 3, xz = 4, and yz = 6, Find the value of x^2 + y^2 + z^2... (answered by Edwin McCravy)

Given: vz/xz = wz/yz Prove: <1 ~=... (answered by Fombitz)

We have YX=9, WX=12, and YZ=5. If YX is perpendicular to WX then what is... (answered by greenestamps,s_p123123)

Let be three positive numbers such that: x^2 + y^2 + z^2 = 2(xy + xz + yz). x + y... (answered by CPhill,ikleyn)