SOLUTION: {{{ 2x+(2/3)y=-8 }}}
{{{ (1/2)x-(1/3)y=1 }}}
Algebra.Com
Question 97584:
Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1st: 2x +(2/3)y =-8
2nd: (1/2)x -(1/3)y = 1
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Multiply thru 2nd by 2:
1st: 2x + (2/3)y = -8
3rd: x - (2/3)y = 2
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Add 1st and 3rd to solve for "x":
3x = -6
x = -2
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Substitute into 1st (or 2nd) to solve for y:
2*-2 + (2/3)y = -8
-4 + (2/3)y = -8
(2/3)y = -4
y = -6
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Check the answer in 2nd.
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Cheers,
Stan H.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
multiply 3 times the top equation. 6x+2y=-24
multiply 6 times the bottom equation. 3x-2y=6 no more fractions.
add the equations vertically. 9x=-18
x=-2
-6-2y=6
-2y=12
y=-6
Check:
2*-2+2/3*-6=-8...-4-4=-8
1/2*-2-1/3*-6=1...-1+2=1
Ed
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