SOLUTION: Hello! I need help on solving these systems of equations, quadratic {{{9y^2+77x-190=0}}}, {{{14x^2-9y^2-7x-6=0}}}

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Question 972410: Hello! I need help on solving these systems of equations, quadratic
,
Found 2 solutions by amarjeeth123, MathTherapy:
Answer by amarjeeth123(569)   (Show Source): You can put this solution on YOUR website!
9y^2+77x-190=0..........equation 1
14x^2-9y^2-7x-6=0.......equation 2
9y^2=190-77x............equation 3
Substituting equation 1 in 2 we get
14x^2-9y^2-7x-6=0
14x^2-190+77x-7x-6=0
14x^2+70x-196=0
x^2+5x-14=0
x^2+7x-2x-14=0
x(x+7)-2(x+7)=0
(x-2)(x+7)=0
x=2
Substituting in equation 1 we get,
9y^2+154-190=0
9y^2=36
y^2=4
y=2
x=2 and y=2 is the solution.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Hello! I need help on solving these systems of equations, quadratic
,

       ---- eq (i)

 ------- eq (ii)

 ------- Adding eqs (ii) & (i)





(x + 7)(x - 2) = 0

x + 7 = 0          OR        x - 2 = 0





If x = - 7

 ---- eq (i)













Thus, we get: 

If x = 2

 ---- eq (i)













Thus, we get:  

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