SOLUTION: Given the function f(x) = 2x^2 + 3x - 1 , find the value(s) of k so that f(k+2) = -2. - I nee help how to start off and what lesson to use. Thank you!

Question 943356: Given the function f(x) = 2x^2 + 3x - 1 , find the value(s) of k so that f(k+2) = -2.
- I nee help how to start off and what lesson to use. Thank you!
Found 2 solutions by reviewermath, MathLover1:
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
Given the function f(x) = 2x^2 + 3x - 1 , find the value(s) of k so that f(k+2) = -2.
Solution:
In f(x) = 2x^2 + 3x - 1, replace x by (k+2), the result is
f(k+2) = 2(k+2)^2 + 3(k+2) - 1
-2 = 2(k^2 + 4k + 4) + (3k + 6) - 1
-2 = 2k^2 + 11k + 13
2k^2 + 11k + 15 = 0
(2k + 5)(k + 3) = 0
2k + 5 = 0 or k + 3 = 0
Therefore, k = -5/2 or k = -3
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

Given the function , find the value(s) of k so that .

solutions:
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check one solution:
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