SOLUTION: How to solve this Polynomial Equation in the complex plane.
{{{Z^4+2z^3+20z+12=0}}}
Ty for your time!
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Question 909201: How to solve this Polynomial Equation in the complex plane.
Ty for your time!
Found 2 solutions by josgarithmetic, richwmiller:
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
Try using synthetic division to check for roots of -1, -2, -3, and -4. If any give remainder of zero, then that number checked is a root. Each time a root is found, the numbers in the quotient become the coefficients of a factor one degree less than the dividend used.
Need more help?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Be consistent with the variables. Z is not the same as z
z^4+2z^3+0*z^2+20z+12=0
It has no integer zeros
(z^2-2z+6) (z^2+4z+2) = 0
It has two real z = sqrt(2)-2, z = -sqrt(2)-2 and
two complex solutions z = 1+i sqrt(5), z = 1-i sqrt(5)
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