your equation is 1 + (1/x^2) = 3/x)
multiply both sides of the equation by x^2 to get:
x^2 + 1 = 3x
subtract 3x from both sides of the equation to get:
x^2 - 3x + 1 = 0
use the quadratic formula to solve for x.
you will get x = (3 +/- sqrt(5)) / 2
this is equivalent to x = 3/2 +/- sqrt(5)/2
that should be selection a.
the quadratic formula is:
x = -b +/- sqrt(b^2 - 4ac)
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2a
your formula has to be in the standard form of ax^2 + bx + c = 0
your formula is x^2 - 3x + 1 = 0
you get:
a = 1
b = -3
c = 1
replace a and b and c in the formula and solve for x.