SOLUTION: 3rs-s^2=2 and 2r-3s=-4. Please solve and explain ,thanks

Question 856323: 3rs-s^2=2 and 2r-3s=-4. Please solve and explain ,thanks
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
3rs-s^2=2
2r-3s=-4
.
2r=3s-4
r=(3s-4)/2
.
3s((3s-4)/2)-s^2=2
(9s^2-12s)/2-s^2=2
9s^2-12s-2s^2=4
7s^2-12s-4=0
s= -2/7, s=2 See below. I'll let you figure out r.
.
Ed
.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=256 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 2, -0.285714285714286. Here's your graph:

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