SOLUTION: I have 2 questions: 1. {{{y=5^(x)}}} {{{y=5^(2x) -1}}} 2. {{{y=2e^(2x)}}} {{{y=e^(x) -1}}}

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Question 852351: I have 2 questions:
1.

2.

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
The first one seems potentially quadratic in form, when adjusted right.


-
Let . This makes .
Substituting you make


or
-
Back-substituting from those two solutions for u,
NEG SQRT VERSION
-----the right member would become negative, and you cannot raise 5 to any power to get a negative number. Reject This Equation.
POS SQRT VERSION
-----THIS we can use. Irrational.
....
Choose your logarithm base. Here, using base ten:




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