SOLUTION: x^2+y^2=12
xy=-3
Algebra.Com
Question 815906: x^2+y^2=12
xy=-3
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Try and substitute into the circle equation:
not factorable.
First solve for x^2 according to solution to quadratic formula;
and then
x=-(6-3*sqrt(3)) or x=(6-3*sqrt(3)) or x=-(6+3*sqrt(3)) or x=(6+3*sqrt(3))
'
FINAL ANSWER FOR JUST x: or or or
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