SOLUTION: x-y+z=1
3x+y-2z=-3
x+4y-z=2
Algebra.Com
Question 754410: x-y+z=1
3x+y-2z=-3
x+4y-z=2
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x-y+z=1
3x+y-2z=-3
x+4y-z=2
==============
--> (0,-1,-2)
-------------
I use determinants.
---
You can use elimination.
Add eqn 1 & 3, then add eqn1*2 to eqn 3.
That gives 2 eqns in x & y.
etc.
RELATED QUESTIONS
x+2y-z=3
2x-y+z=3... (answered by ankor@dixie-net.com)
2x+3y+z -3x-2z-7 ( -Z'3-2z+z (-Z 3 is third power))-2z+z
__xy-3z_____________ (answered by midwood_trail)
Gauss Jordan method for... (answered by ikleyn)
solvex,y,z using matrix 3x-4y-z=-1
x=y-z=-2
(answered by MathLover1)
X+y+z+=8
-x-y+2z=-4
3x+5y-7z=14
2x-3y+z=-1
X+4y+5=25... (answered by Boreal)
Solve by using matrix method
2x-y+z=3
x+2y-z=3... (answered by stanbon)
solve using cramer rule :- 3x+2y+4z=19 2x-y+z=3 6x+7y-z=7
x-y+2z=1 x+y+z=2 2x-y+z=5... (answered by ikleyn)
Solve by matrix method
x+y-z=1,... (answered by Fombitz)
solve using cramer rule :- 3x+2y+4z=19 2x-y+z=3 6x+7y-z=7
x-y+z= 1 x+y+z=2 2x-y+z=5... (answered by ikleyn)