SOLUTION: solve each system by the substitution method.
1) 2x^2-y^2=6
2) y=x^2-3
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Question 750196: solve each system by the substitution method.
1) 2x^2-y^2=6
2) y=x^2-3
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
so y=0 or y=2
y=0:
or
y=2:
or
solutions
(-sqrt(3),0)
(sqrt(3),0)
(-sqrt(5),2)
(sqrt(5),2)
:)
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