the sum of the two-digit number is 11. When the number is reversed, the number is 63 less than the original number. Find the original number and show work.
What is asked in the problem?
Find the original number
Given:
The sum of the two-digit number is 11
When the number is reversed, the number is 63 less than the original number
Representation:
Let t = tens digit
u = unit digit
10t + u = the original two-digit number
10u + t = the reversed two-digit number
Equation:Translate the given sentences to mathematical sentences
t + u = 11
10u + t = (10t + u) - 63 Simplify
9u - 9t = -63 Divide both sides by 9
u - t = -7
Solve the two equation simultaneously by elimination or substitution.
I will use elimination method
t + u = 11
-t + u = -7
____________
2u = 4 divide 2 both sides
u = 2
Substitute u = 2, to any of the two equations to find the other variable t.
t + u = 11, u = 2
t + 2 = 11
t = 11 - 2
t = 9
To find the original number, substitute t = 9 and u = 2
10t + u = 10(9) + 2
= 90 + 2
= 92 -------------->> answer
If you want to check substitute t = 9 and u = 2 to any of the two equations
then if the two equation are true after substituting, then you're answer
is correct.
Happy calculating
Rachel