SOLUTION: passing through (6, -3), and perpendicular to the line whose equation is x - 3y - 2 = 0 the equation of the line in point slope form is

Question 722011: passing through (6, -3), and perpendicular to the line whose equation is x - 3y - 2 = 0 the equation of the line in point slope form is
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
-3 y = -1 x + 2
Divide by -3
y = 1/ 3 x + - 2/3
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = 1/3

The slope of a line perpendicular to the above line will be the negative reciprocal -3
Because m1*m2 =-1
The slope of the required line will be -3

m= -3 ,point ( 6 , -3 )
Find b by plugging the values of m & the point in
y=mx+b
-3 = -18 + b
b= 15
m= -3
The required equation is y = -3 x + 15
m.ananth@hotmail.ca

RELATED QUESTIONS
Use the given conditions to write an equation for the line in point slope form and... (answered by Fombitz)

Passing through (5,−3) and perpendicular to the line whose equation is x−5y−4=0... (answered by ewatrrr)

Find the equation for the line passing through the point (-1,-4) and perpendicular to the (answered by checkley77)

Use the given conditions to write an equation for each line in point-slope form.... (answered by lwsshak3)

Use the given conditions to write an equation for each line in point-slope form.... (answered by Cromlix,Fombitz,anand429)

What is the equation of the line described below written in slope-intercept form? the... (answered by TimothyLamb)

Find the general form of the equation of a line passing through the point (1,-2) and... (answered by josgarithmetic)