SOLUTION: how to solve this system
x+y+z=28
x^2+y^2+z^2=336
Were x,y,z are terms of geometric sequence
Algebra.Com
Question 705214: how to solve this system
x+y+z=28
x^2+y^2+z^2=336
Were x,y,z are terms of geometric sequence
Answer by mouk(232) (Show Source): You can put this solution on YOUR website!
You have TWO equation in THREE unknowns so there is no solution
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