given f(x)=1/x and g(x)=2/x^2 find f+g(-3) a.-5/9 b.-1/9 c.1/2 d. 1/12 Thanks That just means to add f(-3) and g(-3) f(x) = 1/x f(-3) = 1/(-3) f(-3) = -1/3 g(x) = 2/x² g(-3) = 2/(-3)² g(-3) = 2/9 Therefore (f+g)(-3) = f(-3)+g(-3) = -1/3 + 2/9 = -3/9 + 2/9 = -1/9 (choice b) Edwin