SOLUTION: given: f(a)=(sqrt)a^2+3a, find a(-2) Thanks!

Algebra.Com
Question 69396: given: f(a)=(sqrt)a^2+3a, find a(-2)

Thanks!

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
f(a)=(sqrt)a^2+3a, find a(-2)
f(-2)=sqrt((-2)^2)+3(-2)
f(-2)= sqrt(4)-6
f(-2)=2-6
f(-2)=-4
Cheers,
Stan H.

RELATED QUESTIONS

Given that f(x) = sqrt (3-x) , find f(m + 2). A) sqrt (1-m) B) sqrt (m+2-x) C)... (answered by checkley77)
solve for a {{{ sqrt( 2a+7 )-sqrt( 3a+2 )=0... (answered by MathLover1)
Given that k = 2 sqrt (3a - k^2), express k in terms of... (answered by josgarithmetic)
Given that k = 2 (sqrt 3a - k^2), express k in terms of... (answered by ikleyn)
3. Simplify (81a^8b^2) ^1/4 A. 81a^2b^1/2 B. 3a^2 sqrt |b| *Am pretty sure this is... (answered by robertb)
given: f(x)=x^2+3 and g(x)(sqrt)2-x find f o g (x) a.5-x b. 1-x c. (sqrt) 5-x^3 d.... (answered by funmath)
{{{a^2+3a+2}}} (answered by sudhanshu_kmr)
(a^2+3a)/(a^2-3a-18)? (answered by josgarithmetic)
3a/2 = a -... (answered by elima)