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---->(1)

--->(2)
This time we have an ellipse and a hyperbola. Neither one are in standard form however
if we just add the two equations we will eliminate the y’s from the system
for that multiply equation(2) by -11 we get

--->(3)
Now adding equation (1) and equation(3) we get

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solve for x.

x= +/-2
To determine the value(s) of the y’s we can substitute these into either of the equations.
x=2

x=-2

Therefore the solutions are :(2,0) (-2,0)