SOLUTION: 4x^2-4y^2=196 3x^2+y^2=147 Hello can anyone solve this for me? I get really confused with the ^2 in this question and keep getting funny answers.

Question 677532: 4x^2-4y^2=196
3x^2+y^2=147
Hello can anyone solve this for me?
I get really confused with the ^2 in this question and keep getting funny answers.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Hint:

3x^2+y^2=147

y^2 = -3x^2 + 147

y^2 = -3x^2 + 147

-----------------------

4x^2-4y^2=196

4x^2-4y^2=196

4x^2-4(-3x^2 + 147)=196

4x^2-4(-3x^2 + 147)=196

4x^2-4(-3x^2) - 4(147) = 196

4x^2 + 12x^2 - 588 = 196

Now solve for x. Use the solutions for x to find the corresponding solutions for y.
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