SOLUTION: Consider the following two equations. 8s + 2t = x t + 4s = -1 If there are an infinite number of real-valued solutions for s and t, what must be the value of x? After

Question 65637: Consider the following two equations.
8s + 2t = x
t + 4s = -1
If there are an infinite number of real-valued solutions for s and t, what must be the value of x?
After solving the problem, the answer i got was 2, however, according to the book the right answer is negative 2. How do u solve this problem?
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Try this:
8s+2t = x
t+4s = -1 Multiply this by 2 and rewrite it as: 2t = -8s-2 then substitute into the first equation.
8s+(-8s-2) = x Simplify.
8s-8s-2 = x
x = -2
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