# SOLUTION: x+y=5 x+2z=6 y+3z=4 Please solve this system of equations

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 Algebra: Systems of equations that are not linear Solvers Lessons Answers archive Quiz In Depth

 Question 65554: x+y=5 x+2z=6 y+3z=4 Please solve this system of equationsAnswer by chitra(359)   (Show Source): You can put this solution on YOUR website!THE GIVEN SYSTEM OF EQUATIONS ARE: X + Y = 5 ------------> (1) X + 2Z = 6 ------------> (2) Y + 3Z = 4 ------------> (3) ADDING (1) AND (3), WE GET: X + 2Y + 3Z = 9 ---------->(4) ADDING (2) AND (3), WE GET: X + Y + 5Z = 10 ---------->(5) SUBTRACTING (4) AND (5), WE GET: Y - 2Z = -1 ----------->(6) SUBTRACTING (6) FROM (3), WE GET: -5Z = - 5 THIS IMPLIES Z = 1 SUBSTITUTE THE VALUE OF Z IN (6), WE GET: Y - 2(1) = -1 Y = -1 + 2 Y = 1 NOW, SUBSTITUTE THE VALUE OF Y IN (1), WE GET: X + 1 = 5 X = 5 - 1 X = 4 HENCE, THE VALUES OF X, Y AND Z ARE: X = 4, Y = 1 AND Z = 1 HENCE THE SOLUTION. HAPPY CALCULATING........!!!!!!!!