SOLUTION: x+y+z=8 x-y-z=-4 -x+y-z=-8 Please solve this system of equations.

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The given system of equations are:

x + y + z = 8 -----------(1)

x - y - z = -4 --------- (2)

-x + y - z = -8 -----------(3)


Adding (1) and (2), we get:

2x = 4


this implies x = 2


Adding (2) and (3), we get:

-2z = -12

z = 6

Substituting the values of x and zin (1), we get y = 0

Thus the solution.

x = 2, y = 0 and z = 6