SOLUTION: If f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3 and g(x)= x^2 + 1/3x + 1
calculate final answers as rational (fraction) numbers reduced to the lowest terms.
PLEASE HELP...THIS PROBLEM
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-> SOLUTION: If f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3 and g(x)= x^2 + 1/3x + 1
calculate final answers as rational (fraction) numbers reduced to the lowest terms.
PLEASE HELP...THIS PROBLEM
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Question 64214: If f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3 and g(x)= x^2 + 1/3x + 1
calculate final answers as rational (fraction) numbers reduced to the lowest terms.
PLEASE HELP...THIS PROBLEM IS VERY CONFUSING. I WOULD APPRECIATE IT A LOT! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3 and g(x)= x^2 + 1/3x + 1
calculate final answers as rational (fraction) numbers reduced to the lowest terms.
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f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3
If I assume the x-factors are in the denominator I get:
A least common denominator of 2x^3.
Then f(x)=1/lcd +x/lcd + x^2/lcd +x^3/lcd
Rewrite to get:
f(x)=[1+x+x^2+x^3]/3x^3
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g(x)= x^2 + 1/3x + 1
lcd=3x
g(x)= 3x^3/lcd + 1/lcd + 3x/lcd
g(x)=[3x^3+1+3x]/3x
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Cheers,
Stan H.
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