SOLUTION: Hi! Could someone please help me with this problem.
Let x=4,y=-3 and z=2
xy^2-3z^2
-----------
(xy)^2(-3z)^2
Algebra.Com
Question 64111: Hi! Could someone please help me with this problem.
Let x=4,y=-3 and z=2
xy^2-3z^2
-----------
(xy)^2(-3z)^2
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
xy^2-3z^2 ......=4*(-3)^2-3(2)^2=4*9-3*4=36-12=24
-----------.........---------------------------------------------------------
(xy)^2(-3z)^2...=(4*-3)^2(-3*2)^2=-12^2*-6^2=144*36=5184
24/5184=1/216
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